Alcohols, Phenols and Ethers for NEET UG

Alcohols, phenols and ethers all contain C–O bonds, yet they behave very differently. Learn their preparation, acidity and the reactions NEET asks about most.

ChemistryClass 1276 MCQs2 lessons13 flashcards3 memory tricks

Practise Alcohols, Phenols and Ethers free

What you'll learn

  1. Alcohols: preparation and reactions
    Prepare alcohols, tell 1°, 2° and 3° alcohols apart, and predict oxidation and dehydration products.
  2. Phenols and ethers
    Explain why phenol is acidic, predict ring substitution, and recall ether reactions.

Key formulas

Acid strengthcarboxylic acid > phenol > water > alcohol

Memory tricks

Lucas testTertiary alcohol is in a hurry; primary runs on IST (Indian Stretchable Time).

With conc. HCl + ZnCl₂, 3° alcohols turn cloudy immediately, 2° in about 5 minutes, and 1° not at room temperature.

Acidity of phenolPhenoxide spreads its negative charge round the ring, so it is happier than ethoxide.

Phenol > water > ethanol in acidity. Nitro groups at ortho/para increase it further; picric acid (2,4,6-trinitrophenol) is strongly acidic.

Williamson synthesisUse a primary halide, or the alkoxide just knocks off an H and you get an alkene.

R–O⁻Na⁺ + R'–X (1°) → R–O–R'. With 3° halides, elimination wins.

Try 3 NEET-style questions

Q1. Aspirin (acetylsalicylic acid) is made by acetylating

  1. salicylic acid
  2. phenol
  3. benzoic acid
  4. salicylaldehyde
Show answer

Answer: (1) salicylic acid

Salicylic acid (2-hydroxybenzoic acid) reacts with acetic anhydride to acetylate its phenolic –OH, forming aspirin.

Q2. Among ethanol, phenol, water and p-nitrophenol, the weakest acid is

  1. Phenol
  2. Water
  3. p-Nitrophenol
  4. Ethanol
Show answer

Answer: (4) Ethanol

Ethanol is weaker than water; phenols are more acidic than both.

Q3. Propene undergoes hydroboration–oxidation (B₂H₆, then H₂O₂/OH⁻). The product is

  1. propan-2-ol
  2. propan-1-ol
  3. propanal
  4. propane-1,2-diol
Show answer

Answer: (2) propan-1-ol

Boron adds to the less substituted carbon, and oxidation replaces it with –OH. The net result is anti-Markovnikov addition of water, giving propan-1-ol.

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